Evaluate $(53)^{2}$ by using the identity $(a + b)^{2} = a^{2} + 2 a b + b^{2}$

Open in App

Solution

Using $(a + b)^{2}$ = $a^{2} + 2 a b + b^{2}$
We can write $(53) a s (50 + 3)^{2}$
$\Rightarrow$ $(50 + 3)^{2}$ = $50^{2} + 2 \times 50 \times 3 + 3^{2}$ $=$ $2500 + 300 + 9$
Hence the answer is $2809$

Suggest Corrections

Similar questions

(9.8)^{2}

(a - b)^{2} = a^{2} - 2 a b + b^{2}

209^{2}

{(a + b)}^{2} = a^{2} + 2 a b + b^{2}

\sqrt{\frac{a^{2} + 2 a b + b^{2}}{a^{2} - 2 a b + b^{2}}}

(a + b)^{2} = a^{2} + 2 a b + b^{2}

(a + 6)^{2}

(a - b)^{2} = a^{2} - 2 a b + b^{2}

(5 a - 4 b)^{2}

Join BYJU'S Learning Program