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Question

Evaluate:
π/2011+cosxdx.

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Solution

π/20 11+cosxdx.
we know 1+cosx=2cos2x2
12π/20 sec2x2dx
[22tanx2]π/20 =tanπ4-0=1

1211641_1362822_ans_898d2f1c2b1c465187f7be86f1410c37.JPG

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