Evaluate- -0-3-x3 -1- dx

The correct option is C 94 √(3) Consider, I= ∫_0^√(3)[x^3 1] dx ⇒ I= [x^44 x]^√(3)_0 I=94 √(3) ...

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Standard XII

Mathematics

First Fundamental Theorem of Calculus

Evaluate: ∫...

Question

Evaluate: $\int_{0}^{\sqrt{3}} [x^{3} - 1] d x$

\frac{1}{4} - \sqrt{3}

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\frac{1}{4} - \sqrt{2}

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\frac{9}{4} - \sqrt{3}

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\frac{9}{4} - \sqrt{2}

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Solution

The correct option is C $\frac{9}{4} - \sqrt{3}$
Consider, $I = \int_{0}^{\sqrt{3}} [x^{3} - 1] d x$

$\Rightarrow I = {[\frac{x^{4}}{4} - x]}_{0}^{\sqrt{3}}$

$I = \frac{9}{4} - \sqrt{3}$

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Evaluate: ∫√30[x3−1]dx

The correct option is C 94−√3Consider, I=∫√30[x3−1]dx⇒I=[x44−x]√30I=94−√3

Evaluate: $\int_{0}^{\sqrt{3}} [x^{3} - 1] d x$

The correct option is C $\frac{9}{4} - \sqrt{3}$
Consider, $I = \int_{0}^{\sqrt{3}} [x^{3} - 1] d x$

$\Rightarrow I = {[\frac{x^{4}}{4} - x]}_{0}^{\sqrt{3}}$

$I = \frac{9}{4} - \sqrt{3}$