Question

Evaluate : $\int (1-\frac{x^2}{2!}+\frac{x^4}{4!}-\dots \dots \dots \dots )dx$

• A. $\sin x+c$
• B. $-\sin x+c$
• C. $\cos x+c$
• D. $-\cos x+c$

Answer 1

The correct option is A $\sin x+c$

$\int (1-\frac{x^2}{2!}+\frac{x^4}{4!}-------)dx$

We know that binomial expansion of $\cos x=1-\frac{x^2}{2!}+\frac{x^4}{4!}--------$

So $\int (1-\frac{x^2}{2!}+\frac{x^4}{4!}--------)dx=\int \cos xdx=\sin x+c$

$=\sin x+c$