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Question

Evaluate dxx(xn+1)
(where C is constant of integration)

A
1nln|1+xn|+C
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B
1nln|1+xn|+C
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C
1nln|1+xn|+C
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D
1nln|1+xn|+C
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Solution

The correct option is A 1nln|1+xn|+C
Let I=dxx(xn+1)
I=dxxxn(1+xn)
I=xn11+xndx
Put 1+xn=t
nxn1dx=dt
I=dt(n)t=1ndtt=1nln|t|+C
I=1nln|1+xn|+C

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