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Question

Evaluate x7dx(1x2)5
(where C is constant of integration)

A
x88(1x2)4+C
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B
x88(1x2)4+C
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C
x48(1x2)4+C
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D
x48(1x2)4+C
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Solution

The correct option is B x88(1x2)4+C
Let I=x7dx(1x2)5=x7dxx10(x21)5
I=x3dx(x21)5
Put : x21=t
2x3dx=dt
I=12dtt5
I=12t5dt=12t44+C
I=181(x21)4+C
I=x88(1x2)4+C

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