Question

Evaluate:

$\int \log xdx$

Answer 1

Given: $\int \log xdx$

$u=\log x;v=1$

$\Rightarrow du=\frac{1}{x};\int vdx=x$

$\Rightarrow x\log x-\int dx$

$\Rightarrow x\log x-x+c$