CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
277
You visited us 277 times! Enjoying our articles? Unlock Full Access!
Question

Evaluate: 1+sinxdx

Open in App
Solution

I= 1+sinxdx

(cosx2+sinx2)dx

=sinx21/2cosx21/2+c=2sinx22cosx2+c

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Implicit Differentiation
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon