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Question

Evaluate: xddx(lnx+x22) dx

A
x2+x33+c
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B
lnx+x33+c
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C
lnx+x22+c
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D
x+x33+c
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Solution

The correct option is C x+x33+c

I=xddx(lnx+x22)dx=x(1x+x)dxI=(1+x2)dxI=x+x33+C


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