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Question

Evaluate (4a+3b)2−(4a−3b)2+48ab

A
96a
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B
96ab
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C
45b
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D
26ab
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Solution

The correct option is B 96ab
(4a+3b)2(4a3b)2+48ab
Using,
(ab)2=(a22ab+b2) and (a+b)2=(a2+2ab+b2)
=[(4a)2+2(4a)(3b)+(3b)2][(4a)22(4a)(3b)+(3b)2]+48ab
=16a2+24ab+9b216a2+24ab9b2+48ab
=96ab

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