Question

Evaluate:

${\left(\frac{1}{4}\right)}^{-2}-3(32{)}^{\frac{2}{5}}\times (7{)}^0+{\left(\frac{9}{16}\right)}^{-\frac{1}{2}}$ is $5\frac{1}{m}$, then
value of $m$ is

Answer 1

${\left(\frac{1}{4}\right)}^{-2}-3(32{)}^{\frac{2}{5}}\times (7{)}^0+{\left(\frac{9}{16}\right)}^{-\frac{1}{2}}$
$=4^2-3(2^5{)}^{\frac{2}{5}}\times 1+{\left(\frac{3^2}{4^2}\right)}^{-\frac{1}{2}}$
$=16-3\times 4+\frac{4}{3}$
$=16-12+\frac{4}{3}$
$=4+\frac{4}{3}$
$=\frac{12+4}{3}$
$=\frac{16}{3}$
$=5\frac{1}{3}$