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Question

Evaluate limx0⎜ ⎜ ⎜ ⎜ ⎜ ⎜(1+x)1xe+ex2sin2x⎟ ⎟ ⎟ ⎟ ⎟ ⎟

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Solution

Given expressions limx0((1+x)1/xe+ex2sin2x)
limx0(1+x12+1(1x)2!+1(1x)(12x)2!+....)e+ex2(sinxx)2.x2
limx0(ee+ex2x2)
Apply L-Hospital Rule
limx0(e/22x)
limx0(0)=0

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