Question

Evaluate: $\underset{x\to -3}{lim}\frac{x^3+27}{x+3}$

• A. $9$
• B. $27$
• C. $-27$
• D. $0$

Answer 1

The correct option is B $27$

$\underset{x\to -3}{lim}\frac{x^3+27}{x+3}=\underset{x\to -3}{lim}\frac{x^3-{(-3)}^3}{x^1-{(-3)}^1}=\frac{3}{1}{(-3)}^{3-1}=3\times 9=27$