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Byju's Answer
Standard XII
Mathematics
Implicit Differentiation
Evaluate each...
Question
Evaluate each of the following:
(i)
cosec
-
1
cosec
π
4
(ii)
cosec
-
1
cosec
3
π
4
(iii)
cosec
-
1
cosec
6
π
5
(iv)
cosec
-
1
cosec
11
π
6
(v)
cosec
-
1
cosec
13
π
6
(vi)
cosec
-
1
cosec
-
9
π
4
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Solution
We know that
cosec
-
1
cosecθ
=
θ
, [−π/2, 0) ⋃ ( 0, π/2]
(i)
cosec
-
1
cosec
π
4
=
π
4
(ii)
cosec
-
1
cosec
3
π
4
=
cosec
-
1
cosec
π
-
π
4
=
cosec
-
1
cosec
π
4
=
π
4
(iii)
cosec
-
1
cosec
6
π
5
=
cosec
-
1
cosec
π
+
π
5
=
cosec
-
1
cosec
-
π
5
=
-
π
5
(iv)
cosec
-
1
cosec
11
π
6
=
cosec
-
1
cosec
2
π
-
π
6
=
cosec
-
1
cosec
-
π
6
=
-
π
6
(v)
cosec
-
1
cosec
13
π
6
=
cosec
-
1
cosec
2
π
+
π
6
=
cosec
-
1
cosec
π
6
=
π
6
(vi)
cosec
-
1
cosec
-
9
π
4
=
cosec
-
1
-
cosec
2
π
+
π
4
=
cosec
-
1
-
cosec
π
4
=
cosec
-
1
cosec
-
π
4
=
-
π
4
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0
Similar questions
Q.
Find the principal values of each of the following:
(i)
cosec
-
1
(
-
2
)
(ii)
cosec
-
1
(
-
2
)
(iii)
cosec
-
1
2
3
(iv)
cosec
-
1
2
cos
2
π
3
Q.
Evaluate each of the following:
(i)
cot
-
1
1
3
-
cosec
-
1
-
2
+
sec
-
1
2
3
(ii)
cot
-
1
2
cos
sin
-
1
3
2
(iii)
cosec
-
1
-
2
3
+
2
cot
-
1
-
1
(iv)
tan
-
1
-
1
3
+
cot
-
1
1
3
+
tan
-
1
sin
-
π
2
Q.
For the principal values, evaluate the following:
(i)
sin
-
1
-
3
2
+
cosec
-
1
-
2
3
(ii)
sec
-
1
2
+
2
cosec
-
1
-
2
(iii)
sin
-
1
cos
2
cosec
-
1
-
2
(iv)
cosec
-
1
2
tan
11
π
6
Q.
c
o
s
e
c
θ
(
c
o
s
e
c
θ
−
1
)
+
c
o
s
e
c
θ
(
c
o
s
e
c
θ
+
1
)
=
Q.
Prove that
c
o
s
e
c
θ
(
c
o
s
e
c
θ
−
1
)
+
c
o
s
e
c
θ
(
c
o
s
e
c
θ
+
1
)
=
2
s
e
c
2
θ
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