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Question

Find the value of sec 29cosec 61 + 2cot8cot17cot45cot73cot82.

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Solution

sec 29cosec 61 + 2cot8 cot17 cot45 cot73 cot82

= sec29cosec(9029) + 2cot8 cot17(1) cot(9017) cot(908)

= sec29sec29 + 2cot8 cot17 tan17 tan8 [cot(90θ)=tanθ]

= 1+2cot8cot17.1cot17.1cot8 ....(tanθ=1cotθ)

= 1+2

= 3


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