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Question

Evalute : sec29cosec61 + 2 cot 8 cot 17 cot45 cot73 cot82.

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Solution

sec29cosec61 + 2 cot 8 cot 17 cot45 cot73 cot82

= sec29cosec(9029) + 2 cot 8 cot 17 (1) cot (9017) cot (908)

= sec29sec29 + 2cot 8 cot 17 tan 17 tan 8 ( cot(90θ)=tanθ

= 1 + 2 cot 8 cot 17 1cot17 . 1cot8 .......... ( tanθ=1cotθ)

= 1+2

=3


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