Question

Evaluate :
$\frac{tan{26}^{\circ }}{cot{64}^{\circ }}$___

Answer 1

$\frac{tan{26}^{\circ }}{cot{64}^{\circ }}$

$=\frac{tan({90}^{\circ }-{64}^{\circ })}{cot{64}^{\circ }}$
$=\frac{cot{64}^{\circ }}{cot{64}^{\circ }}=1$ (As, tan (${90}^{\circ }$ - A) = cot A)