Question

The value of : $\frac{tan{26}^{\circ }}{cot{64}^{\circ }}$ equals :

• A. 1
• B. 0
• C. -1
• D. 2

Answer 1

The correct option is A

1

$\frac{tan{26}^{\circ }}{cot{64}^{\circ }}$
= $\frac{tan({90}^{\circ }-{64}^{\circ })}{cot{64}^{\circ }}$
=$\frac{cot{64}^{\circ }}{cot{64}^{\circ }}$ =1 ($\because tan({90}^{\circ }-A)=cotA)$