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Question

Evaluate :
i. π/20(sinx+cosx)dx
ii. 10(3x2+4)dx
iii. 10(3e3x+ex)dx

A
i. 2
ii. 5
iii.e41e
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B
i. 3
ii. 4
iii.e31e
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C
i. 9
ii. 5
iii.e312e
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D
i. 1
ii. 4
iii.e313e
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Solution

The correct option is A i. 2
ii. 5
iii.e41e
a. π/20(sinx+cosx)dx
=[cosx]π/20+[sinx]π/20=(0+1)+(10)=2
b. 10(3x2+4)dx=[x3]10+4[x]10=1+4=5
c. 10(3e3x+exdx=[e3x]10+[ex]10
e31)+(1e+1)=e41e

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