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Question

Evaluate: 3x5dx

A
3x225x+C
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B
3x227x+C
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C
3x224x+C
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D
3x226x+C
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Solution

The correct option is A 3x225x+C
We know that,
(P+Q)dx=Pdx+Qdx
kPdx=kPdx {where k is a constant}
Hence ,
(3x5)dx=3xdx5dx
xdx=x22+C1&dx=x+C2xndx=xn+1n+1+C(3x5)dx=3x225x+C
{C is equal to C1+C2}

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