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Byju's Answer
Standard XII
Mathematics
Differentiation of Inverse Trigonometric Functions
Evaluate : ...
Question
Evaluate :
∫
sin
2
x
−
cos
2
x
sin
x
cos
x
d
x
.
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Solution
We have,
I
=
∫
sin
2
x
−
cos
2
x
sin
x
cos
x
d
x
I
=
−
2
∫
cos
2
x
−
sin
2
x
2
sin
x
cos
x
d
x
I
=
−
2
∫
cos
2
x
sin
2
x
d
x
=
−
2
∫
cot
2
x
d
x
=
−
2
2
ln
|
sin
2
x
|
+
c
=
−
ln
|
sin
2
x
|
+
C
Hence, this is the answer.
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