CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Evaluate dxsin2x+sin2x.

A
12lntanxtanx+2+C
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
12lncotxcotx+2+C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
12lntanxtanx2+C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
12lncotx+2cotx+C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 12lntanxtanx+2+C
I=dxsin2x+sin2x

Multiply numerator and denominator by sec2x
I=sec2xdxtan2x+2tanx

[Substitute tanx=t]sec2xdx=dt

I=dtt2+2t

=12(1t1t+2)dt

=12[ln(t)ln(t+2)]+C

=12[ln(tanx)ln(tanx+2)]+C

=12lntanxtanx+2+C

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon