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Question

Evaluate dxsin2x+sin2x.

A
12lntanxtanx+2+C
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B
12lncotxcotx+2+C
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C
12lntanxtanx2+C
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D
12lncotx+2cotx+C
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Solution

The correct option is A 12lntanxtanx+2+C
I=dxsin2x+sin2x

Multiply numerator and denominator by sec2x
I=sec2xdxtan2x+2tanx

[Substitute tanx=t]sec2xdx=dt

I=dtt2+2t

=12(1t1t+2)dt

=12[ln(t)ln(t+2)]+C

=12[ln(tanx)ln(tanx+2)]+C

=12lntanxtanx+2+C

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