Evaluate : $\int e^{2 x + 3} d x$

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Solution

$I = \int e^{2 x + 3} d x$
Let $2 x + 3 = t$
$2 d x = d t$
$\int e^{2 x + 3} d x = \frac{1}{2} \int e^{t} d t$

$= \frac{1}{2} (e^{t}) + C$

$= \frac{1}{2} (e^{2 x + 3}) + C$

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