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Byju's Answer
Standard XII
Mathematics
Integration by Parts
Evaluate ∫ e...
Question
Evaluate
∫
e
x
(
tan
x
+
1
)
s
e
c
x
d
x
Open in App
Solution
I
=
∫
e
x
(
tan
x
+
1
)
sec
x
d
x
=
∫
e
x
tan
x
sec
x
d
x
+
∫
e
x
sec
x
d
x
According to the integration by parts,
∫
u
v
d
x
=
u
∫
v
d
x
−
∫
(
d
u
d
x
×
∫
v
d
x
)
d
x
H
e
r
e
,
u
=
sec
x
v
=
e
x
S
o
,
∫
sec
x
e
x
d
x
=
sec
x
∫
e
x
d
x
−
∫
(
d
sec
x
d
x
×
∫
e
x
d
x
)
d
x
=
e
x
sec
x
−
∫
(
sec
x
tan
x
e
x
)
d
x
S
o
,
I
=
∫
(
sec
x
tan
x
e
x
)
d
x
+
e
x
sec
x
−
∫
(
sec
x
tan
x
e
x
)
d
x
=
e
x
sec
x
Suggest Corrections
0
Similar questions
Q.
Evaluate
∫
e
x
(
tan
x
−
log
cos
x
)
d
x
Q.
Evaluate:
∫
e
x
(
tan
x
+
log
(
sec
x
)
)
d
x
.
Q.
Assertion :
∫
e
x
(
tan
x
+
sec
2
x
)
d
x
=
e
x
tan
x
+
C
Reason:
∫
e
x
(
f
(
x
)
+
f
′
(
x
)
)
d
x
=
e
x
f
(
x
)
+
C
Q.
Match the following.
I.
∫
e
x
(
sin
x
+
cos
x
)
d
x
=
a)
e
x
tan
x
+
c
II.
∫
e
x
(
cos
x
−
sin
x
)
d
x
=
b)
e
x
log
sec
x
+
c
III.
∫
e
x
(
tan
x
+
sec
2
x
)
d
x
=
c)
e
x
sin
x
+
c
IV.
∫
e
x
(
tan
x
+
log
sec
x
)
d
x
=
d)
e
x
cos
x
+
c
Q.
∫
e
x
(
tan
x
+
sec
2
x
)
d
x
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