Question

Evaluate : $(3a+\frac{1}{2})(3a+\frac{1}{2})$

• A.
• B.
• C.
• D.

Answer 1

The correct option is C

$(a+b{)}^2=a^2+2ab+b^2$
$(3a+\frac{1}{2})(3a+\frac{1}{2})$
=$(3a+\frac{1}{2}{)}^2$
=$(3a{)}^2+2\times 3a\times \frac{1}{2}+(\frac{1}{2}{)}^2$
=$9a^2+3a+\frac{1}{4}$