Evaluate
$(3 x - 2 y) (3 x + 2 y) (9 x^{2} + 4 y^{2})$

Open in App

Solution

$(3 x - 2 y) (3 x + 2 y) (9 x^{2} + 4 y^{2})$
Using $(a - b) (a + b) = a^{2} - b^{2}$
$= (9 x^{2} - 4 y^{2}) (9 x^{2} + 4 y^{2})$
$= 81 x^{4} - 16 y^{4}$

Suggest Corrections

Similar questions

Q. Simplify:

\frac{(3 x - 2 y) (3 x + 4 y) - (3 x + 2 y) (3 x - 2 y)}{(- 4 y^{2} + 6 x y)}

Find the continued products:
(i) $(x + 1) (x - 1) (x^{2} + 1)$
(ii) $(x - 3) (x + 3) (x^{2} + 9)$
(iii) $(3 x - 2 y) (3 x + 2 y) (9 x^{2} + 4 y^{2})$
(iv) $(2 p + 3) (2 p - 3) (4 p^{2} + 9)$

9 x^{2} - 4 y^{2}

can be written as :

Q. State whether the statement is True or False:

(3 x - \frac{1}{2 y}) (3 x + \frac{1}{2 y})

is equal to

9 x^{2} - \frac{1}{4 y^{2}}

Simplify: (3x-2y)(3x+4y)-(3x+2y)(3x-2y)

Join BYJU'S Learning Program

Evaluate(3x−2y)(3x+2y)(9x2+4y2)

(3x−2y)(3x+2y)(9x2+4y2)Using (a−b)(a+b)=a2−b2=(9x2−4y2)(9x2+4y2)=81x4−16y4

Evaluate
$(3 x - 2 y) (3 x + 2 y) (9 x^{2} + 4 y^{2})$

$(3 x - 2 y) (3 x + 2 y) (9 x^{2} + 4 y^{2})$
Using $(a - b) (a + b) = a^{2} - b^{2}$
$= (9 x^{2} - 4 y^{2}) (9 x^{2} + 4 y^{2})$
$= 81 x^{4} - 16 y^{4}$