Question

State whether the statement is True or False:

$(3x-\frac{1}{2y})(3x+\frac{1}{2y})$ is equal to $9x^2-\frac{1}{4y^2}$.

• A. True
• B. False

Answer 1

The correct option is A True

Given, $(3x-\frac{1}{2y})(3x+\frac{1}{2y})$.

We know, $(a+b)(a-b)$ $=(a^2-b^2)$.

Then, on multiplying, we get,

$(3x-\frac{1}{2y})(3x+\frac{1}{2y})$$=(3x{)}^2-(\frac{1}{2y}{)}^2$
$=9x^2-\frac{1}{4y^2}$.

Hence, the statement is true.

Therefore, option $A$ is correct.