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Question

Evaluate : limx1x72x5+1x33x2+2

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Solution

limx1x72x5+1x33x2+2
on differentiating both numertor & denomitator w.r.t x we get
limx1ddx(x72x5+1)ddx(x33x2+2)
limx17x610x43x26x
on putting limit we get
7(1)610(1)43(1)26(1)
7136
=33 =1
Hence limx1x72x5+1x33x2+2
=1
Hence limx1x72x51x33x2+2=1.

1179577_1350603_ans_0cc4e511ea224be98f7cac76a01cfff4.JPG

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