Question

Evaluate
$\log (x+3)+\log (x-3)=\log 16$

Answer 1

A] $log(x+3)+log(x-3)=log16$

$=log\left[\right(x+3\left)\right(x-3\left)\right]=log16$

$=log[x^2-3^2]=log16$

$=x^2-9=16$

$=x^2=25$

$\therefore$ x=5