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Question

Evaluate sin2(π4)+sin2(3π4)+sin2(5π4)+sin2(7π4).

A
1
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B
2
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Solution

The correct option is B 2
We have (sin2(π4)+sin2(7π4))+(sin2(3π4)+sin2(5π4))

=(sin2(π4)+sin2(2ππ4))+(sin2(3π4)+sin2(2π3π4))

=(sin2(π4)+cos2(π4))+(sin2(3π4)+cos2(3π4))=2

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