The correct option is B 6/7 Prime factorization of 1728 and 2744, 1728 = 2^ 6 *3^ 3 2744 = 7^ 3 *2^ 3 1728 / 2744 ...

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Standard VIII

Mathematics

Cube Root Using Prime Factorisation

Evaluate: √...

Question

Evaluate: $\sqrt[3]{\frac{- 1728}{2744}}$

- \frac{6}{11}

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- \frac{6}{7}

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- \frac{3}{4}

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- \frac{12}{17}

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Solution

The correct option is B $- \frac{6}{7}$
$P r i m e f a c t o r i z a t i o n o f 1728 a n d 2744, 1728 = 2^{6} * 3^{3} 2744 = 7^{3} * 2^{3} \frac{- 1728}{2744} = \frac{- 2^{2} * 3}{7^{3} \times 2} \sqrt[3]{\frac{- 1728}{2744}} = \frac{- 6}{7}$

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Similar questions

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\sqrt[3]{[\frac{(- 1728)}{2744}]}

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Evaluate :

$(i) \frac{3}{7} + \frac{- 4}{9} + \frac{- 11}{7} + \frac{7}{9} (i i) \frac{2}{3} + \frac{- 4}{5} + \frac{1}{3} + \frac{2}{5} (i i i) \frac{4}{7} + 0 + \frac{- 8}{9} + \frac{- 13}{7} + \frac{17}{9} (i v) \frac{3}{8} + \frac{- 5}{12} + \frac{3}{7} + \frac{3}{12} + \frac{- 5}{8} + \frac{- 2}{7}$

Evaluate:

$3 (5 x - 7) - 2 (9 x - 11) = 4 (8 x - \frac{1}{3}) - 17$

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Evaluate: 3√−17282744

The correct option is B −67Primefactorizationof1728and2744,1728=26∗332744=73∗23−17282744=−22∗373×23√−17282744=−67

Evaluate: $\sqrt[3]{\frac{- 1728}{2744}}$

The correct option is B $- \frac{6}{7}$
$P r i m e f a c t o r i z a t i o n o f 1728 a n d 2744, 1728 = 2^{6} * 3^{3} 2744 = 7^{3} * 2^{3} \frac{- 1728}{2744} = \frac{- 2^{2} * 3}{7^{3} \times 2} \sqrt[3]{\frac{- 1728}{2744}} = \frac{- 6}{7}$