Question

Evaluate the expression to open gate A:

$5\times 2÷10-1+7-3÷3\times 3$

Answer 1

The given expression consists of multiplication, division, addition and subtraction.

According to PEMDAS rule, first, we perform the multiplication and division operations, one by one, starting from left.

$5\times 2÷10-1+7-3÷3\times 3$
$=10÷10-1+7-3÷3\times 3$
$=1-1+7-3÷3\times 3$
$=1-1+7-1\times 3$
$=1-1+7-3$

Finally, we are left with addition and subtraction operations.

Similarly, we perform both the operations, one by one, starting from left.

$\to 1-1+7-3$
$=0+7-3$
$=7-3$
$=4$

Hence, 4 is the value of the original expression.