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Question

To open gate C, find the value of the expression: 4+2+6÷2×3+1×5


A
20
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B
25
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C
95
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Solution

The correct option is A 20
Let's recall the PEMDAS rule.

P ParenthesisE ExponentsM MultiplicationD DivisionA AdditionS Subtraction

As the expression 4+2+6÷2×3+1×5 contains addition, division and multiplication operation operations, we perform the division and multiplication operation first, moving from left to right.

4+2+6÷2×3+1×5
=4+2+3×3+1×5

Similarly, we perform the subsequent multiplications, one by one, starting from the left.

4+2+3×3+1×5
=4+2+9+1×5
=4+2+9+5

Finally, we perform the addition operations, starting from left.

4+2+9+5
=6+9+5
=15+5
=20

The value of the expression is 20.

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