Question

Evaluate the following :
$\frac{\tan 10}{\cot 80}$

Answer 1

We have $\tan (90-\theta )=\cot \theta$

therefore,

$\tan 10=\tan (90-80)=\cot 80$

To evaluate,

$\frac{\tan 10}{\cot 80}$

$=\frac{\cot 80}{\cot 80}$

$=1$