Evaluate the following limits:
limx→π2(π2−x)tanx
Let y=π2−x
as x→π2,y→0
=limy→0ytan(π2−y)
=limy→0y cot y
=limy→0ycos ysin y
=limy→0cos ylimy→0ysin y
=limy→0cos y1limy→0sin yy
=1×11=1
limx→a(x+2)52−(a+2)52x−a