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Question

Evaluate the H.C.F and L.C.M of the polynomial (x+4)3(x+1) and (x+1)(x2+4x+16).

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Solution

Let f(x)= (x+4)3(x+1) and g(x)= (x+1)(x2+4x+16).
Factor of x2+4x+16=(x+4)2
So, H.C.F = (x+4)2(x+1)
L.C.M = (x+4)3(x+1)

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