Question

Evaluate the limit : $\underset{x\to 3}{lim}\frac{x^2-9}{x+2}$

Answer 1

$\underset{x\to 3}{lim}\frac{x^2-9}{x+2}=\frac{(3{)}^2-9}{3+2}$

$=\frac{9-9}{3+2}=0$

Therefore,

$\underset{x\to 3}{lim}\frac{x^2-9}{x+2}=0$