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Question

Evaluate the product of (2a+3b)(2a3b)

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Solution

The given polynomials are 2a+3b and 2a3b we multiply them as follows:

(2a+3b)(2a3b)=(2a×2a)+(2a×3b)+(3b×2a)+(3b×3b)=4a26ab+6ab9b2
=4a29b2

Hence, (2a+3b)(2a3b)=4a29b2.

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