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Question

Evaluate the value of :
∣ ∣x1y+zy1z+xz1x+y∣ ∣ =

A
1+x+y+z
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B
x+y+z
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C
0
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D
1
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Solution

The correct option is B 0
A=∣ ∣x1y+zy1z+xz1x+y∣ ∣
By column trasformation
C3C3+C1
∣ ∣x1x+y+zy1x+y+zz1x+y+z∣ ∣
take common (x+y+z)
(x+y+z)∣ ∣x11y11z11∣ ∣
So two rows are same
So, A=0

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