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Question

Evaluate without actual multiplication.
501×501

A
251021
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B
251521
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C
251001
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D
None of the above
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Solution

The correct option is C 251001
We know 501×501 =(500+1)(500+1)
=(500+1)2
We know suitable identity is (x+y)2=x2+2xy+y2
Therefore, the value of (500+1)2 is
=(500)2+2(500)(1)+(1)2
=250000+1000+1
=251001

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