wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Evaluate :

x+λxxxx+λxxxx+λ

Open in App
Solution

=x + λxxxx + λxxxx + λ= λ 0x-λ λx0-λ x + λ ApplyingC1C1 -C2, C2C2-C3= λ 0x -λ 0 2x +λ 0-λ x + λ Applying R1R2+R3= λ02x +λ -λx + λ + x-λ 0 0-λ= λ[λ(2x + λ)] + xλ2= λ2 (2x + λ + λ2x)= 3λ2x + λ3= λ2 (3x + λ )

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Standard Expansions and Standard Limits
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon