Evalute : sec29∘cosec61∘ + 2 cot 8∘ cot 17∘ cot45∘ cot73∘ cot82∘.
sec29∘cosec61∘ + 2 cot 8∘ cot 17∘ cot45∘ cot73∘ cot82∘
= sec29∘cosec(90∘−29∘) + 2 cot 8∘ cot 17∘ (1) cot (90∘−17∘) cot (90∘−8∘)
= sec29∘sec29∘ + 2cot 8∘ cot 17∘ tan 17∘ tan 8∘ (∵ cot(90∘−θ)=tanθ
= 1 + 2 cot 8∘ cot 17∘ 1cot17∘ . 1cot8∘ .......... (∵ tanθ=1cotθ)
= 1+2
=3