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Question

Examine the consistency of the system of equationsx+y+z=1, 2x+3y+2z=2, ax+ay+2az=4

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Solution

Given system of equations
x+y+z=1
2x+3y+2z=2
ax+ay+2az=4
This can be written as
AX=B
where A=111232aa2a,X=xyz,B=124

Here, |A|=1(6a2a)1(4a2a)+1(2a3a)
|A|=a0
Since, |A|0
Hence, the system of equations is consistent.

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