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Standard XII

Chemistry

Oxidation and Reduction

Excess of K...

Question

Excess of $K I$ reacts with $C u S O_{4}$ solution and then $N a_{2} S_{2} O_{3}$ solution is added to it. Which of the following statements is incorrect for these reactions?

N a_{2} S_{2} O_{3}

is oxidised

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C u I_{2}

is formed

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C u_{2} I_{2}

is formed

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Evolved

I_{2}

is reduced

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Solution

The correct option is A $C u I_{2}$ is formed
The reactions that take place when excess of $K I$ reacts with $C u S O_{4}$ and then adding $N a_{2} S_{2} O_{3}$ are shown below:

$4 K I + 2 C u S O_{4} \to I_{2} + C u_{2} I_{2} + 2 K_{2} S O_{4}$
$I_{2} + 2 N a_{2} S_{2} O_{3} \to N a_{2} S_{4} O_{6} + 2 N a I$

During this process, $C u_{2} I_{2}$ is formed while $C u I_{2}$ is not formed. $N a_{2} S_{2} O_{3}$ reduces the liberated iodine.

In the second reaction, the oxidation state of iodine changes from $0$ to $- 1,$ while that of sulphur changes from $+ 2$ to $+ 2.5$ .

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Similar questions

Excess of KI reacts with $C u S O_{4}$ solution and then $N a_{2} S_{2} O_{3}$ solution is added to it. Which of the following statement is incorrect from this reaction

Q. Excess of

K I

reacts with

C u S O_{4}

solution and then

N a_{2} S_{2} O_{3}

solution is added to it.

Which of the statements is incorrect in this reaction?

2.5

g sample of copper is dissolved in excess of

H_{2} S O_{4}

to prepare

100

ml of

0.02 M C u S O_{4} (a q)

10

ml of

0.02 M

solution of

C u S O_{4} (a q)

is mixed with excess of

K I

to show the following changes:

C u S O_{4} + 2 K I ⟶ K_{2} S O_{4} + C u I_{2}

2 C u I_{2} ⟶ C u_{2} I_{2} + I_{2}

The liberated iodine is titrated with hypo (

N a_{2} S_{2} O_{3}

) which requires

V

ml of

0.1 M

hypo solution for its complete reduction.The amount of

I_{2}

liberated in the reaction of

10

ml of

0.02 M

solution with excess

K I

is :

C u S O_{4}

reacts with excess amount of

K I

followed by solution of

N a_{2} S_{2} O_{3}

. In this process which of the following statement is correct?

2.5

g sample of copper is dissolved in excess of

H_{2} S O_{4}

to prepare

100

ml of

0.02 M C u S O_{4} (a q)

10

ml of

0.02 M

solution of

C u S O_{4} (a q)

is mixed with excess of

K I

to show the following changes:

C u S O_{4} + 2 K I ⟶ K_{2} S O_{4} + C u I_{2}

2 C u I_{2} ⟶ C u_{2} I_{2} + I_{2}

The liberated iodine is titrated with hypo (

N a_{2} S_{2} O_{3}

) which requires

V

ml of

0.1 M

hypo solution for its complete reduction.

The color of the solution developed during the addition of

K I

C u S O_{4}

solution is :

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Excess of KI reacts with CuSO4 solution and then Na2S2O3 solution is added to it. Which of the following statements is incorrect for these reactions?

Excess of $K I$ reacts with $C u S O_{4}$ solution and then $N a_{2} S_{2} O_{3}$ solution is added to it. Which of the following statements is incorrect for these reactions?