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Question

Excess of KI reacts with CuSO4 solution and then Na2S2O3 solution is added to it. Which of the following statements is incorrect for these reactions?

A
Na2S2O3 is oxidised
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B
CuI2 is formed
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C
Cu2I2 is formed
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D
Evolved I2 is reduced
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Solution

The correct option is A CuI2 is formed
The reactions that take place when excess of KI reacts with CuSO4 and then adding Na2S2O3 are shown below:

4KI+2CuSO4I2+Cu2I2+2K2SO4
I2+2Na2S2O3Na2S4O6+2NaI

During this process, Cu2I2 is formed while CuI2 is not formed. Na2S2O3 reduces the liberated iodine.

In the second reaction, the oxidation state of iodine changes from 0 to 1, while that of sulphur changes from +2 to +2.5.

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