Excess of KI reacts with CuSO4 solution and then Na2S2O3 solution is added to it. Which of the following statements is incorrect for this reaction?
A
Evolved I2 is reduced by Na2S2O3.
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B
CuI2 is formed.
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C
Na2S2O3 is oxidised.
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D
Cu2I2 is formed.
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Solution
The correct option is ACuI2 is formed. It is given that an excess of KI reacts with CuSO4 solution and then Na2S2O3 is added to it. This is hypo test and reactions are as follows:
2CuSO4+4KI→2K2SO4+2CuI+I2
2Na2S2O3+I2→Na2S4O6+2NaI
CuI2 is not formed according to the following reaction.