CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Excess of KI reacts with CuSO4 solution and then Na2S2O3 solution is added to it. Which of the following statements is incorrect for this reaction?

A
Evolved I2 is reduced by Na2S2O3.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
CuI2 is formed.
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
Na2S2O3 is oxidised.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Cu2I2 is formed.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A CuI2 is formed.
It is given that an excess of KI reacts with CuSO4 solution and then Na2S2O3 is added to it. This is hypo test and reactions are as follows:

2CuSO4+4KI2K2SO4+2CuI+I2
2Na2S2O3+I2Na2S4O6+2NaI

CuI2 is not formed according to the following reaction.
2CuI2(unstable)2CuI+I2

Hence, the statement in option B is incorrect.

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Electrode Potential and emf
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon