Expand $(2 x - {\frac{1}{2 x}}^{2})$

Open in App

Solution

$(2 x - \frac{1}{2 x})^{2} = (2 x)^{2} - 2 (2 x) (\frac{1}{2 x}) + (\frac{1}{2 x})^{2} = 4 x^{2} - 2 + \frac{1}{4 x^{2}} = 4 x^{2} + \frac{1}{4 x^{2}} - 2$

Suggest Corrections

Similar questions

4 x^{4} + 8 x^{3} + 8 x^{2} + 4 x + 1.

{(x + 5 + \frac{1}{2 x})}^{2}

Expand :

(i) $(2 a + b)^{2}$

(ii) $(a - 2 b)^{2}$

(iii) ${(a + \frac{1}{2 a})}^{2}$

(iv) ${(2 a - \frac{1}{a})}^{2}$

(v) $(a + b - c)^{2}$

(vi) $(a - b + c)^{2}$

(vii) ${(3 x + \frac{1}{3 x})}^{2}$

(viii) ${(2 x - \frac{1}{2 x})}^{2}$

\int \frac{2 x - 1}{2 x^{2} + 2 x + 1} d x =

2 x^{7} - 128 x

Join BYJU'S Learning Program