Binomial Theorem
Trending Questions
The sum of the series equals
none of these
- 100C15
- 100C16
- − 100C16
- − 100C15
The value of is equal to
Using binomial theorem, prove that 23n−7n−1 is divisible by 49, where n∈N.
- a=1
- a=2
- n=8
- n=4
Using binomial theorem evaluate each of the following:
(i)(96)3(ii)(102)5(iii)(101)4(iv)(98)5
If n is a positive integer, prove 33n−26n−1 is divisible by 676.
Using binomial theorem, write down the expansions of the following: (i)(2x+3y)5
(ii)(2x−3y)4
(iii)(x−1x)6
(iv)(1−3x)7
(v)(ax−bx)6
(vi)(√xa−√ax)6
(vii)(3√x−3√a)6
(viii)(1+2x−3x2)5
(ix)(x+1−1x)3
(x)(1−2x+3x2)3
- α<β
- γ<δ
- α+δ=β+γ−1
- γ+δ=0
Using binomial theorem determine which number is larger (1.2)4000 or 800?
- 1005
- 2010
- 4020
- 8040
a∗b=ab2∀ a, b ∈ Q−{0} is
- 2
- 0
- None of these
- 1
Find the cube root of by prime factorization method.
- 1575
- 1023
- 961
- 2047
- (x+3a)5
- (x+2a)5
- (x+a)5
- (x+4a)5
- 10
- 5
- 1
- 15
- b2−4ac>0
- b2−4ac≠0
- b2−4ac≤0
- b and c have the same sign as that of a
- 15
- 45
- 14
- 34
then -
- N is equal to the coefficient of x100 in (1−x)200
- The number of zeros at the end of N is only one.
- N=3101×k, where k is an integer
- N is equal to the number of ways of distributing 200 different objects among 2 persons equally.
- 7C2x5a2
- 7C3x4a3
- 7C4x3a4
- 7C6x1a6
Prove that : 1 P(1, 1) + 2.P(2, 2) +3.P(3, 3)+...+ n.P (n, n)= P(n+1, n+1)-1.
then -
- N is equal to the coefficient of x100 in (1−x)200
- The number of zeros at the end of N is only one.
- N=3101×k, where k is an integer
- N is equal to the number of ways of distributing 200 different objects among 2 persons equally.
1⋅2+2⋅22+3⋅23+⋯+n⋅2n=(n−1)2n+1+2
- 48
- 165
- 455
- 495
Using binomial theorem, prove that 33n+2−8b−9 is divisible by 64, n∈N.
- 1928
- 1736
- 1728
- 1936
- 1
- 2
- 2n
- 22n