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Question

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(i) (2a − 5b − 7c)2
(ii) (−3a + 4b − 5c)2
(iii) 12a-14a+22

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Solution

i 2a-5b-7c2=2a+-5b+-7c2 =2a2+-5b2+-7c2+22a-5b+2-5b-7c+22a-7c =4a2+25b2+49c2-20ab+70bc-28ac

ii -3a+4b-5c2=-3a+4b+-5c2 =-3a2+4b2+-5c2+2-3a4b+24b-5c+2-3a-5c =9a2+16b2+25c2-24ab-40bc+30ac

iii 12a-14b+22=a2+-b4+22 =a22+-b42+22+2a2-b4+2-b42+2a22 =a24+b216+4-ab4-b+2a

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